python 实现冒泡排序
下面先列出正确答案:
l = [4, 2, 1, 5, 7, 3]
for i in range(len(l)):
for n in range(i+1, len(l)):
if l[i] > l[n]:
l[i], l[n] = l[n], l[i]
print l
下面这个写法是错的,
下面先列出正确答案:
l = [4, 2, 1, 5, 7, 3]
for i in range(len(l)):
for n in range(i+1, len(l)):
if l[i] > l[n]:
l[i], l[n] = l[n], l[i]
print l
下面这个写法是错的,